Potassium oxide (K_{2}O) is the simplest oxide of potassium with a pale-yellow colour. Let us discuss how K_{2}O reacts with H_{2}SO_{4} in this article.

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**H _{2}SO_{4} and K_{2}O neutralise each other to tát generate a salt and release water. Sulphuric acid (H_{2}SO_{4}) is a powerful dehydrating agent of organic chemistry. It is a colourless and odourless viscous liquid. Potassium oxide (K_{2}O) is a highly reactive ionic compound with a basic character.**

We will discuss many important facts about the H_{2}SO_{4} + K_{2}O reaction, lượt thích enthalpy of formation, type of reaction and products in this article.

**What is the product of ****H**_{2}SO_{4} and **K**_{2}O

**H**and

_{2}SO_{4}**K**

_{2}O**Potassium sulphate (K _{2}SO_{4}) and Water (H_{2}O) are the products of H_{2}SO_{4} and K_{2}O reactions. The chemical equation for this reaction is:**

**K _{2}O + H_{2}SO_{4} = K_{2}SO_{4} + H_{2}O**

**What type of reaction is ****H**_{2}SO_{4} + **K**_{2}O

**H**+

_{2}SO_{4}**K**

_{2}O**H _{2}SO_{4} + K_{2}O reaction is an acid-base (neutralisation) reaction. Here H_{2}SO_{4} is acid and K_{2}O is a base.**

**How to tát balance ****H**_{2}SO_{4} + **K**_{2}O

**H**+_{2}SO_{4}**K**_{2}O**The balanced chemical equation for H**_{2}**SO**_{4}** + K**_{2}**O reaction is,**

**K _{2}O + H_{2}SO_{4} = K_{2}SO_{4} + H_{2}O**

**The general chemical equation for the above reaction is,**

**K**_{2}O + H_{2}SO_{4}= K_{2}SO_{4}+ H_{2}O

**Check if the number of atoms present on both sides of the chemical equation is equal or not.**

**Here the number of atoms is equal. Therefore, the equation is already balanced.**

**Thus, the balanced chemical equation is,**

**K**_{2}O + H_{2}SO_{4}= K_{2}SO_{4}+ H_{2}O

**H**_{2}SO_{4} + **K**_{2}O titration

**titration**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O titration is an acid-base titration. Concentration of Sulphuric acid can be determined using the procedure mentioned below:**

**Apparatus Used:**

**Burette, conical flask, beaker, burette stand, pipette.**

**Indicator:**

**Phenolphthalein is the indicator used for strong acid-strong base titration. **

**Procedure:**

**Wash and rinse the burette with a standardised solution of K**_{2}O and fit it in a burette stand.

**Pipette out 10mL of H**_{2}SO_{4}in the conical flask and add 2-3 drops of phenolphthalein to tát it.

**Start adding the K**_{2}O solution to tát the conical flask in a dropwise manner.

**The colour of the solution will change from colourless to tát light pink when the endpoint is reached.**

**Repeat the above steps to tát get concurrent readings.**

**Contraction of sulphuric acid is found using the formula S**_{H2SO4}V_{H2SO4}= S_{K2O}V_{K2O}.

**H**_{2}SO_{4} + **K**_{2}O net ionic equation

**net ionic equation**

**H**+_{2}SO_{4}**K**_{2}O**H**_{2}**SO**_{4}** + K**_{2}**O net ionic equation is,**

**2H ^{+} (aq.) + O^{2-} (aq.) = H_{2}O (l)**

**Write the general balanced chemical equation of H**_{2}SO_{4}+ K_{2}O.

**K**_{2}O + H_{2}SO_{4}= K_{2}SO_{4}+ H_{2}O

**Display the chemical state of every compound involved during the reaction**

**K**_{2}O (aq.) + H_{2}SO_{4}(aq.) = K_{2}SO_{4}(aq.) + H_{2}O (l)

**Split the strong electrolytes into their respective ions having positive and negative charges.**

**2H**^{+}(aq.) + SO_{4}^{2-}(aq.) + 2K^{+}(aq.) + O^{2-}(aq.) = 2K^{+}(aq.) + SO_{4}^{2-}(aq.) + H_{2}O (l)

**Eliminate the spectator ions to tát obtain the net ionic equation.**

**2H**^{+}(aq.) + O^{2-}(aq.) = H_{2}O (l)

**H**_{2}SO_{4} + **K**_{2}O conjugate pairs

**conjugate pairs**

**H**+_{2}SO_{4}**K**_{2}O**The pair of H**_{2}**SO**_{4}** + K**_{2}**O itself does not have any conjugate pair.**

**H**_{2}SO_{4}and HSO_{4}^{–}size a conjugate acid-base pair.

**The conjugate pair of H**_{2}O contains its conjugate base OH^{–}.

**H**_{2}SO_{4} + **K**_{2}O intermolecular forces

**intermolecular forces**

**H**+_{2}SO_{4}**K**_{2}OXem thêm: Review những đôi giày sneaker nữ hot nhất hiện nay

**H _{2}SO_{4} + K_{2}O reaction has the following intermolecular forces,**

**The intermolecular forces in H**_{2}O molecules are dipole-dipole interaction and intramolecular hydrogen bonding.

**H**_{2}SO_{4}contains London dispersion forces, dipole-dipole interaction and hydrogen bonding between their molecules.

**Ionic bonding is present in K**_{2}SO_{4}because it is an ionic compound.

**H**_{2}SO_{4} + **K**_{2}O reaction enthalpy

**reaction enthalpy**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O reaction enthalpy is -427.4 kJ/mol. The standard enthalpy of formation of compounds involved in the reaction is:**

Molecules | Reaction enthalpy (in kJ/mol) |
---|---|

H_{2}SO_{4} | -909.27 |

K_{2}O | -363.17 |

K_{2}SO_{4} | -1161.65 |

H_{2}O | -285.83 |

**Reaction enthalpy of compounds**

**Reaction Enthalpy ΔH**_{f}** = Standard enthalpy of products – Standard enthalpy of reactants**

**Thus, ΔH**_{f}** = (-1161.65 – 285.83) – (-909.27 – 363.17)**

**ΔH**_{f}** = -427.4 kJ/mol.**

**Is ****H**_{2}SO_{4} + **K**_{2}O a buffer solution

**a buffer solution**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is not a buffer solution because H_{2}SO_{4} is a strong acid and we need a weak acid for a solution to tát act as a buffer solution.**

**Is ****H**_{2}SO_{4} + **K**_{2}O a complete reaction

**a complete reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is a complete reaction and no further steps are left to tát proceed.**

**Is ****H**_{2}SO_{4} + **K**_{2}O an exothermic or endothermic reaction

**an exothermic or endothermic reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is an exothermic reaction because the reaction enthalpy has a negative value for the given chemical equation.**

**Is ****H**_{2}SO_{4} + **K**_{2}O a redox reaction

**a redox reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is not a redox reaction because the oxidation state of atoms involved in the reaction remains unchanged throughout the chemical process.**

**Is ****H**_{2}SO_{4} + **K**_{2}O a precipitation reaction

**a precipitation reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is not a precipitation reaction as no solid product is obtained at the kết thúc of the process.**

**Is ****H**_{2}SO_{4} + **K**_{2}O reversible or irreversible reaction

**reversible or irreversible reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is an irreversible reaction because the heat released during the process cannot be reverted back to tát the reaction mixture. **

**Is ****H**_{2}SO_{4} + **K**_{2}O displacement reaction

**displacement reaction**

**H**+_{2}SO_{4}**K**_{2}O**H _{2}SO_{4} + K_{2}O is a double displacement reaction in which H_{2} and K_{2} displace each other from their respective compounds to tát size new products.**

**Conclusion**

This article concludes that H_{2}SO_{4} and K_{2}O neutralise each other completely and size the corresponding salt. H_{2}SO_{4} is acidic and has several laboratory and industrial importance. K_{2}O is one of the strongest bases known till now.

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