Sulphuric acid reacts with natrium fluoride to lớn size the salt cake. Let us study H_{2}SO_{4 }+ Naf reaction in detail.

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**Sulfuric acid is a very important industrial chemical. It is usually used in the production of fertilizers and is crucial in chemical synthesis, oil refining, wastewater processing, and mineral processing. Sodium fluoride is a colorless, white solid used in the fluoridation of drinking water in trace amounts.**

This article studies the various fact of H_{2}SO_{4 }+ NaF reaction lượt thích its product, enthalpy of reaction, reaction type, conjugate pairs, ionic equation, etc.

**What is the product of H**_{2}SO_{4} and NaF?

_{2}SO

_{4}and NaF?

**Sulfuric acid (H _{2}SO_{4}) reacts with sodium fluoride (NaF) to lớn size sodium sulfate (Na_{2}SO_{4}), and hydrofluoric acid (NaF).**

**H _{2}SO_{4} + NaF → Na_{2}SO_{4} + HF**

**What type of reaction is H**_{2}SO_{4} + NaF?

_{2}SO

_{4}+ NaF?

**H _{2}SO_{4} + NaF is a double displacement, endothermic and precipitate reaction.**

**How to lớn balance** **H**_{2}SO_{4} + NaF?

_{2}SO

_{4}+ NaF?

**The given chemical reaction is balanced by following steps:**

**The unbalanced chemical reaction is written as:****H**_{2}SO_{4 + }NaF → Na_{2}SO_{4}+ HF_{ }**The respective number of moles of each element are tabulated as shown below:**

Elements | Reactant | Product |
---|---|---|

Na | 1 | 2 |

F | 1 | 1 |

S | 1 | 1 |

O | 4 | 4 |

H | 2 | 1 |

**Number of moles of elements on reactant and product side**

**The reaction is balanced when the number of moles of each element at left hand side are equal to lớn the number of moles of each element at right hand side.****Here moles of Na and H are unbalanced on either side.****To balance the reaction, multiply 2 each with NaF on reactant side and HF on product side****The Balanced chemical reaction is****H**_{2}SO_{4 }+_{ }2NaF → Na_{2}SO_{4}+ 2HF

**H**_{2}SO_{4} + NaF Titration

_{2}SO

_{4}+ NaF Titration

**H _{2}SO_{4 + }NaF titration is not possible due to lớn the formation of salt. **

**H**_{2}SO_{4} + NaF Net ionic equation

_{2}SO

_{4}+ NaF Net ionic equation

**The net ionic equation for H_{2}SO_{4} + NaF is not possible since all ions are spectator ions in the reaction as shown below:**

**2H ^{+}(aq) + SO_{4}^{2-}(aq) + 2Na^{+}(aq) + 2F^{–}(aq) = 2H^{+}(aq) + 2F^{–}(aq) + 2Na^{+}(aq) + SO_{4}^{2-}(aq)**

**H**_{2}SO_{4} + NaF conjugate pairs

_{2}SO

_{4}+ NaF conjugate pairs

**The conjugate acid-base pairs for H_{2}SO_{4} + NaF are**,

**Conjugate acid of H**_{2}SO_{4}= H_{3}O^{+}**Conjugate base of H**_{2}SO_{4}= HSO_{4}^{–}**Conjugate base of NaF = F**^{–}

**H**_{2}SO_{4} + NaF intermolecular forces

_{2}SO

_{4}+ NaF intermolecular forces

**The intermolecular forces on H _{2}SO_{4} and NaF**

**are**,

- Hydrogen bond
**,****Van der Waals dispersion forces**, and**Dipole-dipole interaction, acts on H**._{2}SO_{4} **Ion- Ion interactions act on NaF**.

**H**_{2}SO_{4} + NaF reaction enthalpy

_{2}SO

_{4}+ NaF reaction enthalpy

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**H _{2}SO_{4} + NaF change in reaction enthalpy is:**

**368.77 kJ/mol**

**Follow the below steps to lớn calculate the change in reaction enthalpy –**

**The reaction enthalpy of formation of each compound on the either side of the reaction is tabulated down as:**

Compounds | Enthalpy (kJ/mol) |
---|---|

H_{2}SO_{4} | -909.27 |

NaF | -573.6 |

Na_{2}SO_{4} | -1387.1 |

HF | 273 |

**Enthalpy of each compound in the reaction.**

**Change in reaction enthalpy = Sum of enthalpies in product side – sum of enthalpies in reactant side.****Change in Enthalpy = (-1387.1+273) – (-909.27-573.6) = 368.77 kJ/mol**

**Is H**_{2}SO_{4} + NaFa buffer solution?

_{2}SO

_{4}+ NaFa buffer solution?

**H _{2}SO_{4} + NaF reaction is not a buffer solution since presence of strong H_{2}SO_{4 }acid takes place during the reaction**.

**Is H**_{2}SO_{4} + NaF a complete reaction?

_{2}SO

_{4}+ NaF a complete reaction?

**H _{2}SO_{4} + NaF is a defined as a complete reaction as at equilibrium complete moles of reactant are consumed into products.**

**Is H**_{2}SO_{4} + NaF an exothermic or endothermic reaction?

_{2}SO

_{4}+ NaF an exothermic or endothermic reaction?

**H _{2}SO_{4} + NaF is an endothermic reaction because the change in enthalpy is +368.77 kJ/mol, which is positive thereby decreasing the temperature.**

**Is H**_{2}SO_{4} + NaF a redox reaction?

_{2}SO

_{4}+ NaF a redox reaction?

**H _{2}SO_{4} + NaF is not redox reaction as no change in the oxidation state is observed.**

**Is H**_{2}SO_{4} + NaF a precipitation reaction?

_{2}SO

_{4}+ NaF a precipitation reaction?

**H _{2}SO_{4} + NaF is a precipitation reaction, due to lớn the formation of Na_{2}SO_{4}, which is sodium salt of sulfuric acid, in the reaction.**

**Is H**_{2}SO_{4} + NaF reversible or irreversible reaction?

_{2}SO

_{4}+ NaF reversible or irreversible reaction?

**H _{2}SO_{4} + NaF is an irreversible reaction, and can only be reversed when there is drastic change in experiment temperature or pressure.**

**Is H**_{2}SO_{4} + NaF displacement reaction?

_{2}SO

_{4}+ NaF displacement reaction?

**H _{2}SO_{4} + NaF reaction is a double displacement (metathesis) reaction. H_{2} is traded with F to lớn size HF and Na if traded with SO_{4} to lớn size Na_{2}SO_{4}.**

**Conclusion**

Reaction of sulfuric acid with sodium fluoride involves formation basic salt and sodium sulphate. Sodium sulfate is mainly used as catalyst in Kraft process of paper pulping, in manufacturing of detergents. Hydrogen fluoride is a colorless liquid or gas used as important feedstock in many pharmaceuticals and petrochemical industries

** **

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